Basic constant velocity graph question

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The discussion centers on a boat's motion described by the equation x = -20t + 200 for t ≤ 10, questioning whether it is correct to say the boat is "approaching the origin." It is clarified that "approaching the origin" means the distance to the origin decreases over time, regardless of the path taken. The concept of VMG (velocity made good) is introduced, emphasizing that the boat's effective approach speed to a goal can vary based on its angle relative to the desired direction. Additionally, the importance of providing complete problem statements for clarity in discussions is highlighted. Overall, the analysis suggests that while the boat may approach the origin, the trajectory and effective speed depend on various factors.
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Homework Statement



A boat is sailing starting from x = 200m.
When interpreting x(position) vs. t(time) graph for this boat with math models x = -20t + 200(t<=10),
Is it right to say "The boat is approaching to the origin" ? (When t <= 10)

Homework Equations



x = -20t + 200(t<=10)

The Attempt at a Solution


I thought it would be yes, but wasn't sure why. What if the boat is moving diagonally? not directly to the origin?
 
Last edited:
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Boat? What boat?

Please provide a complete problem statement.
 
That doesn't answer the original question, but here are some thoughts regarding the diagonal way:

In nautical terms there exists a word for the approaching speed to a goal, if it is not possible -due to which reasons ever – to sail directly in the preferred direction. It’s called VMG (velocity made good) and can be calculated with the actual boat speed over ground SOG multiplied with the cosine of angle α between the course over ground COG and the direction to the goal.

VMG = SOG ⋅ cos(α)

The larger α, the smaller the VMG and therefore the “approaching velocity” to the goal. Making way, the angle α increases and the VMG decreases (except if you point straight ahead to the goal, i.e. α = 0). The boat stops approaching to the goal, if the α = 90°. The distance Dlim, when this limit is reached can be calculated with the initial angle α0 at t=0.

Dlim = -200 ⋅ cos (α0)

The time tlim till this point is reached (assuming the SOG = -20) can be calculated:

tlim = Dlim / SOG

To answer your question in 3.: If -20 is the SOG and not the (partial) velocity in x-direction (i.e. there is the possibility, that the boat moves “diagonally”), the boat will approach to the origin only till the time tlim, afterwards it will move away (and approaching doesn’t apply for all t<=10).
 

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stockzahn said:
That doesn't answer the original question, but here are some thoughts regarding the diagonal way:

That may be true, but the rules here at PF ask those seeking help to post complete problem statements, rather than snippets of a larger problem statement.

It gives prospective helpers all the facts and prevents needless speculation and going back and forth with the OP, trying to extract enough information to make sense of things.
 
First, "approaching to the origin" is bad grammar! It should be just "approaching the origin". And "approaching the origin" just means that the distance to the origin decreases as time passes- it doesn't have to be along a straight line and it doesn't have to be directly toward the origin.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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