How do I simplify (x-5)+(x^2(x-5)) to (x^2+1)(x-5)?

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To simplify the expression (x-5)+(x^2(x-5)) to (x^2+1)(x-5), the distributive law is applied. By factoring out the common term (x-5), the expression can be rewritten as (x-5)(1+x^2). This demonstrates how recognizing common factors can simplify complex expressions. The discussion highlights the importance of understanding factoring techniques in algebra. Ultimately, clarity in the application of mathematical principles can resolve confusion in problem-solving.
naicidrac
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Hello all,
I am stuck and need assistance. I need to know how my solutions manual goes from this (x-5)+(x^2(x-5)) to this (x^2+1)(x-5) ? Thanks for all the help.

Naicidrac
 
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naicidrac said:
Hello all,
I am stuck and need assistance. I need to know how my solutions manual goes from this (x-5)+(x^2(x-5)) to this (x^2+1)(x-5) ? Thanks for all the help.

Naicidrac

Distributive law: a+ x2a= a(1+ x2) no matter what a is.
 
OMG, Thanks for the help. I just could not see it and now it is as plain as day. I do that a lot with math, Ijust get stuck in one path and can't figure it out. Thx for the help and have a great weekend.
 
Good morning I have been refreshing my memory about Leibniz differentiation of integrals and found some useful videos from digital-university.org on YouTube. Although the audio quality is poor and the speaker proceeds a bit slowly, the explanations and processes are clear. However, it seems that one video in the Leibniz rule series is missing. While the videos are still present on YouTube, the referring website no longer exists but is preserved on the internet archive...

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