a_skier
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Homework Statement
Prove that limx[itex]\rightarrow[/itex]cf(x)=L if and only if limh[itex]\rightarrow[/itex]0f(x+h)=L.
Homework Equations
The Attempt at a Solution
I think this is a simple problem, but I am getting caught up in the middle, as I'm not sure if my procedure is a valid way to prove the statement.
Suppose limx[itex]\rightarrow[/itex]cf(x)=L.
Then for each [itex]\epsilon[/itex]>0 there is a [itex]\delta[/itex]>0 so that
if |x-c|<[itex]\delta[/itex] then |f(x)-L|<[itex]\epsilon[/itex].
Let x=c+h. Then if |x-c|<δ [itex]\Rightarrow[/itex] |c+h-c|<δ [itex]\Rightarrow[/itex] |h|<δ. Furthermore, |f(c+h)-L|<ε. And since we assumed limx[itex]\rightarrow[/itex]cf(x)=L, it follows then that limh[itex]\rightarrow[/itex]0f(c+h)=L.*
So my questions is this: it is valid to simply let x=c+h as I did?
*Note, I did not prove the other case, but I just wrote this out so you guys can get a good idea of what my argument is and tell me if it is wrong or not.