Basic manipulating equation algebra problem?

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Homework Help Overview

The discussion revolves around the manipulation of an algebraic equation related to physics, specifically the equation kx^(2) = 2mgh + 2mgx. Participants are exploring how to rearrange this equation into the standard form kx^(2) - 2mgh - 2mgx = 0.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss different methods for rearranging the equation, including subtracting terms from both sides and multiplying by -1. Questions arise about the necessity of these steps and the implications of rearranging the equation in different forms.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on the algebraic manipulation of the equation. Some express uncertainty about the correctness of their approaches, while others clarify that different forms of the equation can be valid. There is no explicit consensus on a single method, but various perspectives are being explored.

Contextual Notes

Participants mention the challenge of approaching the problem without prior knowledge of the expected equation, highlighting the role of instinct and familiarity with algebraic conventions in problem-solving.

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nchin said:
How did this:
kx^(2) = 2mgh + 2mgx

Subtract 2mgh from both sides, then subtract 2mgx from both sides

i thought it's
kx^(2) = 2mgh + 2mgx
0 = 2mgh + 2mgx - kx^(2) ?
You can do it that way, too. Now multiply every term on both sides by -1
 
NascentOxygen said:
Subtract 2mgh from both sides, then subtract 2mgx from both sides


You can do it that way, too. Now multiply every term on both sides by -1

why do we need to mult both side by -1?
 
nchin said:
why do we need to mult both side by -1?
That gets you the equation that you were expecting to see, but by a different route.
 
NascentOxygen said:
That gets you the equation that you were expecting to see, but by a different route.
but what if you don't know the correct equation?

If i was doing this problem from scratch (without solution manuel)

I wouldn't have known this equation [0 = 2mgh + 2mgx - kx^(2)] was wrong because algebraically, i am correct.

is it like instincts from reading the problem to know what kind of equation to expect or something?
 
nchin said:
How did this:
kx^(2) = 2mgh + 2mgx
become this
kx^(2) - 2mgh - 2mgx = 0
Do you want to solve for x or what?
 
lep11 said:
Do you want to solve for x or what?

yes.
 
nchin said:
yes.
Okay, now you got kx^(2) - 2mgh - 2mgx = 0 so you can use the quadratic formula to solve for x.
 
nchin said:
but what if you don't know the correct equation?

If i was doing this problem from scratch (without solution manuel)

I wouldn't have known this equation [0 = 2mgh + 2mgx - kx^(2)] was wrong because algebraically, i am correct.
It's not wrong. It's perfectly correct.

In general, it is customary to arrange the terms in decreasing degree, and with the leading term having a positive coefficient, e.g., x2 - 4x + 3 = 0

But this is just for appearances (and it makes it easier to comprehend), it's not wrong if you don't do this.

Multiplying both sides does not change anything material. If you do the same thing to both sides of an equation, you change nothing.
 

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