Basic Special Relativity (Time Dilation)

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Homework Help Overview

The discussion revolves around a problem in special relativity, specifically focusing on time dilation as experienced by two atomic clocks, one on a moving Concorde and one at rest. The original poster attempts to calculate the time difference between the two clocks based on the Concorde's travel distance and speed.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of time taken based on distance and speed, questioning the application of the Lorentz factor due to the relatively low speed compared to the speed of light. Some participants suggest using the binomial approximation to simplify calculations, while others express confusion about how to derive the expected time difference from the equations provided.

Discussion Status

The discussion is active, with participants exploring different mathematical approaches and clarifying the use of approximations. Some guidance has been offered regarding rearranging equations, but there is still uncertainty about the calculations leading to the expected result.

Contextual Notes

Participants note the challenge of achieving sufficient precision in calculations and the potential for misunderstanding in manipulating the equations related to time dilation.

bmb2009
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Homework Statement



The Concorde traveled 8000km between two places with an average speed of 375 m/s. What is the time difference between two atomic clocks, one on the train and one at rest with respect to the train?

Homework Equations



T=AT' where A is the Lorentz gamma factor

The Attempt at a Solution



Seemed simple enough the distance divided by time would yield the T (the time taken from the rest frame) so (8x10^6 m/s)/(375) and then solve for T' (proper time which would be the time of a clock on the train correct?) but the speed of 375 m/s is so miniscule in comparison to the speed of light the lorentz factor comes out to be 1 (which isn't surprising) but in the back of the book it says the answer is 16.7 microseconds...what am I doing wrong? Thanks
 
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To a good approximation for your problem, you can approximate [1-(v/c)2]1/2 using the binomial approximation (1-x)a≈1-ax for x<<1.
 
bmb2009 said:

Homework Statement



The Concorde traveled 8000km between two places with an average speed of 375 m/s. What is the time difference between two atomic clocks, one on the train and one at rest with respect to the train?

Homework Equations



T=AT' where A is the Lorentz gamma factor

The Attempt at a Solution



Seemed simple enough the distance divided by time would yield the T (the time taken from the rest frame) so (8x10^6 m/s)/(375) and then solve for T' (proper time which would be the time of a clock on the train correct?) but the speed of 375 m/s is so miniscule in comparison to the speed of light the lorentz factor comes out to be 1 (which isn't surprising) but in the back of the book it says the answer is 16.7 microseconds...what am I doing wrong? Thanks

Not using a calculator with enough precision?
 
TSny said:
To a good approximation for your problem, you can approximate [1-(v/c)2]1/2 using the binomial approximation (1-x)a≈1-ax for x<<1.
How does this help though? that just makes 1-ax = 1 - (7.8125e-13) which still is very close to 1. Where/how do you produce the 16.7 nanoseconds?
 
Last edited:
Use the binomial approximation in the equation T = AT' without plugging any numbers in yet. Then see if you can rearrange for the quantity T-T'. Then plug in numbers.
 
TSny said:
Use the binomial approximation in the equation T = AT' without plugging any numbers in yet. Then see if you can rearrange for the quantity T-T'. Then plug in numbers.

I don't think you can )easily) solve for T-T' with the expansion... T=T'/1-ax ==> T-Tax=T'...unless I am missing some simply algebra i don't see how to manipulate to solve for T-T'
 
bmb2009 said:
I don't think you can )easily) solve for T-T' with the expansion... T=T'/1-ax ==> T-Tax=T'...unless I am missing some simply algebra i don't see how to manipulate to solve for T-T'

Rearrange your last equation as T - T' = Tax

As you said in your original post, you know how to get T for the right hand side.
 
TSny said:
Rearrange your last equation as T - T' = Tax

As you said in your original post, you know how to get T for the right hand side.

ahhh finally got it.. Thanks a bunch!
 

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