What is the Molecular Weight of Each Compound in Moles/Grams for BaCl2 and NaF?

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SUMMARY

The discussion focuses on calculating the molecular weights and stoichiometric requirements for the reaction between Barium Chloride (BaCl2) and Sodium Fluoride (NaF) to produce Barium Fluoride (BaF2) and Sodium Chloride (NaCl). The molecular weight of BaF2 is established as 173.31 g/mol, leading to the conclusion that 0.57 moles of BaF2 requires 0.57 moles of BaCl2 and 1.14 moles of NaF. This translates to 118.77 grams of BaCl2 and 47.89 grams of NaF needed to produce the desired amount of BaF2.

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Homework Statement



BaCl2+ 2NaF -->BaF2 + 2NaCl

Homework Equations



See above...how to get 100g of the BaF2 product?

The Attempt at a Solution


Did molecular weight of each compound in moles/g
 
Physics news on Phys.org
Found MW for BaF2 as 173.31
Then took 100g/173.31 to get 0.57 moles. Did MW for other compounds now not sure where to go from here?
 
Have you read the linked page?

How many moles of BaCl2 needed to produce 0.57 moles of BaF2?

How many moles of NaF needed to produce 0.57 moles of BaF2?
 
Need 1.14moles to produce 0.57 moles BaF2
Need 0.57 BaCl2 moles to produce 0.57 moles BaF2
So I need 47.89g of NaF
And 118.77g of BaCl2
Is that right?
 
Wasn't that hard :smile:
 
My noodle is definitely warm now hehe
TY
 

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