1. The problem statement, all variables and given/known data A uniform rod with a length of 10 meters and a mass of 20 kilograms has a 20 kilogram mass on one end and a 40 kilogram mass on the other end. Where should the fulcrum be located for this beam to balance? ________________ | V | |20kg| |40Kg| 2. Relevant equations Torque = Force * Radius 3. The attempt at a solution Usually when i did problems like this i'm pretty sure the board was considered mass-less, and i'm not sure how to do it now that it has mass. Is calculus needed? Anyway, lets consider: 20 kg mass = m1 @ r1 40 Kg mass = m2 @ r2 and then to figure in the boards mass can we just consider it to have a center of mass on each side (that obviously depends on where the fulcrum is)? if so.... Left side of board = m3 @ r3 right side of board = m4 @ r4 (m1g*r1) + (m3g*r3) - (m2g*r2) - (m4g*r4)=0 m1g + m2g + m3g + m4g = Normal force of fulcrum Anyway i'm a little stuck obviously ..