(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A uniform rod with a length of 10 meters and a mass of 20 kilograms has a 20 kilogram mass on one end and a 40 kilogram mass on the other end. Where should the fulcrum be located for this beam to balance?

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| V |

|20kg| |40Kg|

2. Relevant equations

Torque = Force * Radius

3. The attempt at a solution

Usually when i did problems like this i'm pretty sure the board was considered mass-less, and i'm not sure how to do it now that it has mass. Is calculus needed?

Anyway, lets consider:

20 kg mass = m1 @ r1

40 Kg mass = m2 @ r2

and then to figure in the boards mass can we just consider it to have a center of mass on each side (that obviously depends on where the fulcrum is)?

if so....

Left side of board = m3 @ r3

right side of board = m4 @ r4

(m1g*r1) + (m3g*r3) - (m2g*r2) - (m4g*r4)=0

m1g + m2g + m3g + m4g = Normal force of fulcrum

Anyway i'm a little stuck obviously ..

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# Basic torque fulcrum problem assitance needed

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