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Basketball hangtime physics problem

  1. May 30, 2012 #1
    1. The problem statement, all variables and given/known data
    A basketball player grabbing a rebound jumps 75.4 cm vertically. How much total time (ascent and descent) does the player spend (a) in the top 13.3 cm of this jump and (b) in the bottom 13.3 cm? Do your results explain why such players seem to hang in the air at the top of a jump?


    2. Relevant equations

    vf^2=vi^2-2ay
    d=v/t

    3. The attempt at a solution
    i got part a correct by using vf^2=vi^2-2ay to find 1.6 m/s then i used d=v/t which i rewrote as t=2y/vi+vf and got .3325 for my answer which was correct. then part b came and i tried to use dy=vit-.5gt^2 and i got .0767 which was wrong
     
  2. jcsd
  3. May 30, 2012 #2
    Hi wbetting!

    You need to find the total time the basketball player is in both ascent and descent. Your equation will only give you one of those. :wink:
     
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