Vertical Jump Time Calculation for Basketball Player

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SUMMARY

The discussion focuses on calculating the time a basketball player spends at specific heights during a vertical jump of 74.7 cm. The player reaches a maximum velocity of 3.83 m/s, with calculated times of 0.0287 seconds at the top 10.6 cm and 0.753 seconds at the bottom 10.6 cm of the jump. The equations used include v = v0 + at and x - x0 = v0*t - 0.5at^2. Clarification is needed regarding the initial velocity (v0) and the provided data for accurate calculations.

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Homework Statement


1.A basketball player, standing near the basket to grab a rebound, jumps 74.7 cm vertically.
A) How much time does the player spend in the top 10.6 cm of his jump?
B)How much time does the player spend in the bottom 10.6 cm of the jump?

Homework Equations


1)v=v0 + at
2)x-x0=v0*t -.5at^2

The Attempt at a Solution


I solved for V=3.83 m/s then i substituted that into the second equation and came out with time spent at top=.0287s and at the bottom=.753s

I only 3 more tries to get the problem right but I am trying to figure what I am doing wrong and how to solve it.
 
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I'm afraid you'll need to give more details of your attempt. How did you manage to "solve for v"? Both of the equations you mention need a v0, and I don't see one in your data...

It would perhaps help if you identify what data you have been given in the question (i.e., name it –*this number is an acceleration, that one is an initial velocity) and what you want to find out.
 

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