Vertical Jump Time Calculation for Basketball Player

In summary, the problem involves a basketball player jumping 74.7 cm vertically near the basket. The goal is to determine the time spent at the top and bottom 10.6 cm of the jump. Using the equations v=v0+at and x-x0=v0*t-.5at^2, the initial velocity is solved for and substituted into the second equation to find the time spent at the top and bottom of the jump to be 0.0287s and 0.753s, respectively. More details of the attempt and data given in the question are needed to solve the problem correctly.
  • #1
Fox_Hound
2
0

Homework Statement


1.A basketball player, standing near the basket to grab a rebound, jumps 74.7 cm vertically.
A) How much time does the player spend in the top 10.6 cm of his jump?
B)How much time does the player spend in the bottom 10.6 cm of the jump?

Homework Equations


1)v=v0 + at
2)x-x0=v0*t -.5at^2

The Attempt at a Solution


I solved for V=3.83 m/s then i substituted that into the second equation and came out with time spent at top=.0287s and at the bottom=.753s

I only 3 more tries to get the problem right but I am trying to figure what I am doing wrong and how to solve it.
 
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  • #2
I'm afraid you'll need to give more details of your attempt. How did you manage to "solve for v"? Both of the equations you mention need a v0, and I don't see one in your data...

It would perhaps help if you identify what data you have been given in the question (i.e., name it –*this number is an acceleration, that one is an initial velocity) and what you want to find out.
 

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What are the key concepts involved in the Constant Acceleration Problem?

The key concepts involved in the Constant Acceleration Problem include the relationships between displacement, velocity, and acceleration, as well as the use of vector quantities and the application of Newton's Second Law of Motion.

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What are some real-world applications of the Constant Acceleration Problem?

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