- #1
Qroid
- 11
- 1
In 1. (see attached), a is attached to ground, so has a voltage of 0 V. The voltage at b is -1 V, so the voltage across the capacitor (Vb-Va) is -1 V.
My understanding is so rusty... What happens when a is now wired to the positive end of a 1.5 V battery, and the negative end of the battery is wired to the ground, as in 2? Specifically, what are the new voltages at a and b, and what is the new voltage drop across the capacitor? Is it still -1 V, or has it changed?
My understanding is so rusty... What happens when a is now wired to the positive end of a 1.5 V battery, and the negative end of the battery is wired to the ground, as in 2? Specifically, what are the new voltages at a and b, and what is the new voltage drop across the capacitor? Is it still -1 V, or has it changed?