Battery and potential difference

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SUMMARY

The discussion focuses on the behavior of potential difference in a parallel plate air gap capacitor when the plates are separated after being charged by a battery. As the distance between the plates increases, the potential difference also increases due to the relationship defined by the formula V = Ed, where E is the electric field and d is the distance. The removal of the battery prevents charge movement, leading to an increase in potential difference as work is required to separate the plates. The concepts of capacitance and the relationship between charge, distance, and area are crucial to understanding this phenomenon.

PREREQUISITES
  • Understanding of parallel plate capacitors
  • Familiarity with electric fields and potential difference
  • Knowledge of capacitance formulas, specifically V = Ed
  • Basic principles of charge movement in capacitors
NEXT STEPS
  • Study the derivation of the capacitance formula for parallel plate capacitors
  • Explore the relationship between electric field strength and potential difference
  • Investigate the effects of dielectric materials on capacitance
  • Learn about energy stored in capacitors and its relation to potential difference
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Students and professionals in electrical engineering, physics enthusiasts, and anyone seeking to deepen their understanding of capacitor behavior and electric potential differences.

thisisfudd
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A battery fully charges a parallel plate air gap capacitor. The battery is removed and the plates are pulled apart. What happens to the potential difference between the plates as they are being separated?

So I guess resistance and I operate over a certain length. So the length is increasing, so that means resistance and length increase, so potential difference increases? Is this correct logic?
 
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What resistance? caps should have infinite resistance between the plates. There is an equation relating charge to the distance between the plates isn't there?
 
Well if the electric field stays the same and distance increases than electric potential would increase. A batterys job is simply to move electrons from one plate to another basically, so with no battery connected no electrons could be moved from each plate to make up for the change in distance and the potential would increase, correct?
 
The Potential would increase, as work is required to move the plates apart.

Claude.
 
When you think capacitance you involve capactiance concepts when trhe question asks about the potential difference between the two plates!

i believe you have a formula for the voltage across two plates in a parallel plate capacitor whjich is related to the charge, distance and area of the two plates. Since you only change one thing d (distance between the plates) V will change accordingly
 

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