- #1

JohnApplebee

- 2

- 0

## Homework Statement

A racket ball is struck in such a way that it leaves the racket with a speed of 5.37 m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 2.15 m from the racket. Find the height of the racket ball when it left the racket.

## Homework Equations

Kinematic equations

## The Attempt at a Solution

I already have the solution BUT it's because I solved for time using the formula time = distance / speed. However, I tried solving for time using the 2-Dimensional kinematic equations involving acceleration (-9.8), time, Inital velocity, etc. I plugged in all the variables except for time and my answer for time came out way wrong. So why is that? What am I doing wrong? Thanks.