Bending moment in a wooden joist with 30 kN load

[barnacksam]

3) A wooden joist of rectangular cross-section spans a gap of 5.0 m and supports a load of 30 kN placed 3.0 m from the right-hand end. The joist has a depth of 150 mm and the maximum tensile strength that it is allowed to withstand is 12 MPa.

a) Calculate the bending moment 1.0 m and 2.0 m from the right-hand end.



M/I = sigma/y = E/R

Have no clue, cheers

 

[Mapes]

Recommend starting with a free-body diagram, then finding the reaction loads.