Bernouilli ODE (where is my mistake?)

[justaboy]

found my mistake... thanks

 

[jackmell]

Homework Statement

Solve the ODE
$$x^2y'+2xy-y^3=0$$

The Attempt at a Solution

$$x^2y'+2xy-y^3=0$$
Substitution:
$$v=y^-2$$
V makes the equation linear:
$$v'-4\frac{v}{x}=-2x^{-2}$$

I get:

$$v'+\frac{4}{x} v=-\frac{2}{x^2}$$