(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A water tank of height h has a small hole at height y. The water is replenished to keep h from changing. The water squirting from the hole has range x. The range approaches zero as y goes to 0 because the water squirts right onto the table. The range also approaches zero as y goes to h because the horizontal velocity becomes zero. Thus there must be some height y between 0 and h for which the range is a maximum.

a)Find an algebraic expression for the flow speed v with which the water exits the hole at height y.

b)Find an algebraic expression for the range of a particle shot horizontally from height y with speed v.

c)Combine your expressions from parts A and B. Find the maximum range x_max

d)Find the height y of the hole.

2. Relevant equations

v1A1=v2A2

p1+.5(density)v1^2+(density)gy1=p2+.5(density)v2^2+(density)gy2

deltaK+deltaU=Wext

3. The attempt at a solution

a)Solving for v2(assuming this is outside the can velocity):

v=sqrt of 2p1/denisty-2p2/density+v1^2+2gy1-2gy2

computer told me to check my answer, so I guess its wrong.

b)distance=rate*time

t=sqrt of 2h/g

x=v*t

haven't tried part c or d cause I cant get part a) right.

Thanks for any help.

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# Homework Help: Bernoulli's equation and a water tank

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