1. The problem statement, all variables and given/known data A water tank of height h has a small hole at height y. The water is replenished to keep h from changing. The water squirting from the hole has range x. The range approaches zero as y goes to 0 because the water squirts right onto the table. The range also approaches zero as y goes to h because the horizontal velocity becomes zero. Thus there must be some height y between 0 and h for which the range is a maximum. a)Find an algebraic expression for the flow speed v with which the water exits the hole at height y. b)Find an algebraic expression for the range of a particle shot horizontally from height y with speed v. c)Combine your expressions from parts A and B. Find the maximum range x_max d)Find the height y of the hole. 2. Relevant equations v1A1=v2A2 p1+.5(density)v1^2+(density)gy1=p2+.5(density)v2^2+(density)gy2 deltaK+deltaU=Wext 3. The attempt at a solution a)Solving for v2(assuming this is outside the can velocity): v=sqrt of 2p1/denisty-2p2/density+v1^2+2gy1-2gy2 computer told me to check my answer, so I guess its wrong. b)distance=rate*time t=sqrt of 2h/g x=v*t haven't tried part c or d cause I cant get part a) right. Thanks for any help.