1. The problem statement, all variables and given/known data A pressurized cylindrical tank, 5m in diameter, contains water which emerges from the pipe at point C with a velocity of 25 m/s. Point A is 10m above point B and point C is 3m above point B. The area of the pipe at point B is 0.07 m2 and the pipe narrows to an area of 0.02m2 at Point C. Assume the water is an ideal fluid in laminar flow. The density of water 1000kg/m3 2. Relevant equations Continuity Equation: VBAB=VCAC Bernouli's equation: Let D = density of water PB + (1/2)DVB2+DghB = PC + (1/2)DVC2+DghC 3. The attempt at a solution Let D = density of water VBAB=VCAC Therefore VB=[VCAC]/AB=[25*0.02]/0.07=7.14m/s PB + (1/2)DVB2+DghB = PC + (1/2)DVC2+DghC Therefore PB = PC + (1/2)DVC2+DghC -(1/2)DVB2-DghB Except PC and PBis unknown so this approach shouldn't work. One of my peers claims it is the same as 1 ATM but I'm doubtful since this does not result in answer which is accurate. I don't see how The pressure at Point C could possibly be 1atm... 2 unknowns .. 1 equation.. not going to work :( correct me if wrong. Upon searching the internet I came across the solution.. which does yield what I firmly believe is the correct answer .. however I don't not understand how this formula came about.. Let D = density of water PB = [VC2/(2G) - VB2/(2G) + y)Dg =(252/(2*9.8) - (7.142/(2*9.8) + 3)*1000*9.8 ~=~ 316410 Pa ~=~ 320 kPa It appears to be some variation of the Bernoulli formula but I need to demonstrate how to take those formulas and make them into this format... which I don't even know where to begin. I don't need to know how to derive the formulas that this one came from .. in other words.. I can just say here's the Bernoulli equation .. rearrange and combine like so and obtain this: (without having to derive the Bernoulli equation itself). Please and thank you.