Water at 20°C flows through a capillary tube with an inside radius of 0.17 mm and a length of 5.9 cm. If the volume flow rate through the capillary is 1.9 cm3/s, what is the pressure difference between the two ends of the capillary? Give your answer in kPa. The viscosity of water at 20°C is 1.0 x 10-3 Pa s.
P(1) + 1/2pv^2 = P(2) + 1/2pv^2
(p1-p2) = 1/2pv2^2-1/2pv1^2
The Attempt at a Solution
i tried using the second equation for difference in pressure but what i get is zero which is unfortunately wrong. Aside from that, using the bernouli's equation number 1 requires for variables i don't have.