Bike Race Problem: Solving for Applied Force, Work, Power & Acceleration

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To solve the bike race problem, key calculations involve determining the applied force required for Contador to maintain a constant speed while climbing a 5-degree incline, factoring in his weight, bike weight, and resistance force. The work done to reach the summit can be calculated using the work formula, while power generated per kilogram of body mass requires the total energy change divided by time. Additional force needed for acceleration over the last 25 seconds can be found using Newton's second law, and the final velocity can be derived from the acceleration. The discussion emphasizes the importance of showing initial problem-solving efforts before receiving assistance. Understanding these concepts is crucial for accurately solving the physics of the scenario.
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Homework Statement



Contador climbs a 5 degree section of road for 8.2 km to the summit in 20 minutes 35 seconds. he is 62kg?
his bike is 8kg and the resistance force is 21 N
What is the applied force needed for contador to move at constant speed?
what is the work done to reach the summit?
how much power does contador generate per kilogram of body mass?
how much additional force is needed if contador accelerates at a rate of .62 m/s^2 for the last 25 seconds?
with what velocity does he finish the race based on this acceleration?

Homework Equations



ke= .5 mv^2
pe=mgh
work=fd
power= delta E/time


The Attempt at a Solution

 
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green123 said:

Homework Statement



Contador climbs a 5 degree section of road for 8.2 km to the summit in 20 minutes 35 seconds. he is 62kg?
his bike is 8kg and the resistance force is 21 N
What is the applied force needed for contador to move at constant speed?
what is the work done to reach the summit?
how much power does contador generate per kilogram of body mass?
how much additional force is needed if contador accelerates at a rate of .62 m/s^2 for the last 25 seconds?
with what velocity does he finish the race based on this acceleration?

Homework Equations



ke= .5 mv^2
pe=mgh
work=fd
power= delta E/time


The Attempt at a Solution


What are your thoughts on this problem? Per Physics Forums rules, you need to show some effort towards a solution before we can give help.
 
Thread 'Correct statement about size of wire to produce larger extension'

Thread 'Correct statement about size of wire to produce larger extension'

The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...
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