Why does alternate way of solving the problems not work?

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Homework Help Overview

The problem involves a 7 kg ball dropped from a height of 20 meters, with a focus on calculating the work done by air resistance given that the ball's speed just before impact is 18 meters per second. The context includes concepts of potential energy and kinetic energy.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the relationship between potential energy and kinetic energy, questioning why a derived kinetic energy value does not correspond to the expected work done by air resistance. There is also mention of the conservation of energy and the effects of air resistance on mechanical energy.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of energy conservation and the implications of air resistance. Some guidance has been provided regarding the nature of kinetic energy and its dependence on velocity, but no consensus has been reached on the specific question posed.

Contextual Notes

There appears to be confusion regarding the calculations related to kinetic energy and the effects of air resistance, with participants noting that the original poster may already understand some underlying principles.

Perseverence
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Homework Statement



Princeton p 411 #6

A 7 kg ball is dropped from 20m. if the speed just before it hits the ground in 18 meters per second, what is the work done by air resistance?[/B]

Homework Equations


KE= (mv^2)*1/2
PE=mgh[/B]

The Attempt at a Solution


Mgh equals 1400 joules. PE equals KE. using the kinetic energy formula I was able to derive that the velocity of the ball without air resistance would be 20 meters per second. Which would be 2 meters per second less than 18 meters per second. Then I calculated the amount of kinetic energy there would be for 2 meters per second he found that it would be 14 joules. Why isn't this the answer for the amount of air resistance? I know how to find the right answer, but why doesn't this work?[/B]
 
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Perseverence said:

Homework Statement



Princeton p 411 #6

A 7 kg ball is dropped from 20m. if the speed just before it hits the ground in 18 meters per second, what is the work done by air resistance?[/B]

Homework Equations


KE= (mv^2)*1/2
PE=mgh[/B]

The Attempt at a Solution


Mgh equals 1400 joules. PE equals KE. using the kinetic energy formula I was able to derive that the velocity of the ball without air resistance would be 20 meters per second. Which would be 2 meters per second less than 18 meters per second. Then I calculated the amount of kinetic energy there would be for 2 meters per second he found that it would be 14 joules. Why isn't this the answer for the amount of air resistance? I know how to find the right answer, but why doesn't this work?[/B]
Kinetic energy varies as the square of velocity. ##(v+2)^2 - v^2 \neq 2^2##.
 
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With no friction/air resistance the total energy is conserved. With friction/air resistance the loss of total mechanical energy is converted to thermal energy. In this case heating of the projectile and the air it passes through.
 
Dr Dr news said:
With no friction/air resistance the total energy is conserved. With friction/air resistance the loss of total mechanical energy is converted to thermal energy. In this case heating of the projectile and the air it passes through.
All true, but sadly nothing to do with the question Perseverence asked, and most likely all well understood by the student already. See tnich"s answer.
 

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