What Is the Binding Energy of the Second Electron in a Hydrogen Ion?

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SUMMARY

The binding energy of the second electron in a hydrogen ion (H−) is analyzed through the potential energy contributions from both the nucleus and the interaction between the two electrons. The potential energy is expressed using Coulomb's law, incorporating the 1s wavefunction of hydrogen. The integral involving the wavefunction and the distance between the electrons presents a challenge, particularly due to the complexity introduced by the r12 term. The discussion emphasizes that while the system shares similarities with helium, it is not a hydrogen-like atom, and a full solution of the two-electron wave function is not required.

PREREQUISITES
  • Understanding of Coulomb potential in quantum mechanics
  • Familiarity with hydrogen wavefunctions, specifically the 1s wavefunction
  • Knowledge of integral calculus, particularly in the context of quantum mechanics
  • Basic concepts of two-electron systems and their energy states
NEXT STEPS
  • Study the derivation of the binding energy for two-electron systems in quantum mechanics
  • Learn about the helium atom's wavefunction and its application to similar systems
  • Explore techniques for solving integrals involving wavefunctions in quantum mechanics
  • Investigate the implications of using approximations in multi-electron systems
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on atomic structure and electron interactions in multi-electron systems.

Antonija
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Homework Statement



The negative H− ion is a two-electron system like the He atom. How large is the binding energy of the second electron?

Homework Equations



For hydrogen-like atoms we can use hydrogen wavefunctions so I did it here. First there is potential to be found and then, multipled with charge, it gives energy. Symbols: r2 is distance from second electron to nucleus, r12 is distance between first and second electron.

The Attempt at a Solution



[/B]
Potential is sum of Coulomb potential between one electron and nucleus, and potential between 2 electrons themselves:


Φ(r2)= -e/(4πε0) * 1/r2 + e/(4πε0) ∫ (Ψ1s(r1))2 /r12 d3r1
I know 1s wavefunction for hydrogen so when I write it, it is proportional to exp(-r1/a0)I can put it into my potential but I don't know how to solve integral with wavefunction, as I have r12 in denominator, which is equal to Ir1-r2II can use cosine law but still can't solve integral. I don't know how to behave with this in integral. Sorry if my equation writing is bad, I'm posting for the first time so still learning...
 
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Antonija said:
For hydrogen-like atoms we can use hydrogen wavefunctions so I did it here.
Well, you do not have a hydrogen-like atom.
Your system has some similarity with a helium atom, but with a lower charge of the nucleus. You might be able to transfer some things from the helium system to the hydrogen atom, although I'm not sure how good that approximation will be. It does not look like the problem asks for a full solution of the two-electron wave function.
 

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