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Binding energy/position of maximum energy value

  1. Feb 15, 2016 #1
    1. The problem statement, all variables and given/known data
    The binding energy of the ion H2+ is -16.3 eV at the equilibrium seperation 0.106 nm. The Hellman-Feynman theorem states taht the force between the nuclei in a molecule can be calculated from the electrostatic repulsion between the nuclei and the electrostatic attraction of the nuclei to the electron distribution. According to this theorem, where must the squared modulus of the electron wave function in H2+ have its maximum value?

    2. Relevant equations
    P(x) = abs(psi(x))^2=1

    3. The attempt at a solution
    Urepulsion = 1/(4*pi*epsilonnaught)*q^2/r= 13 eV
    Uattraction = Ebinding + Urepulsion = -2.7 eV
     
  2. jcsd
  3. Feb 15, 2016 #2

    mfb

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    Staff: Mentor

    The sum of attraction plus repulsion is the binding energy. -2.7 eV + 13 eV is positive, so the whole system would be unbound.

    How do you find the attraction as function of the electron position?
     
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