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Binomial Expansion Question Driving Me Mad

  1. Nov 9, 2006 #1
    Binomial Expansion Question Driving Me Mad!!!

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    This is the last question on my maths sheet, and i must have been staring at it for hours, ive read all my notes and book but i just cant piece it together at all.

    Driving me crazy!

    You guys got any pointers, im really confused
     
  2. jcsd
  3. Nov 10, 2006 #2

    acm

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    a) (1 + x)^n = (n,0) + (n,1)x + ..... + (n,n)x^n
    (1 + x)^2n = (1 + x)^n(1 + x)^n
    Observe that x^n-2 * x^2 = x^n , the Hint shows that the coefficient (n,n-2) = (n,2) thus the coefficient of x^n will be (n,2)^2 and so forth for all powers of n. So it can be assumed that the coefficient of x^n = (n,0)^2 + (n,1)^2 + ..... + (n,n)^2.

    b) Obvious, by expansion. (1 + x)^2n = (2n, 0) + .... + (2n,n)x^n + ....+ (2n,2n)x^2n.

    c)By equating coefficients (2n,n) = (n,0)^2 + (n,1)^2 + .... + (n,n)^2
    The definition of (2n,n) = (2n)!/n!(2n-n)! = (2n)!/(n!)^2 as required.
     
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