Biomechanics Problem- Impulse and projectile motion

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Talyyr
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Homework Statement


A long jump trial, the vertical ground reaction force of an athlete’s take-off
leg was measured as shown below. At foot strike, the horizontal velocity of the take -off leg was
8.00 m/s and the vertical velocity of the take-off leg was -2.30 m/s.

(Chart as Attachment)


a) Given that he weighed 850 N, how far and how high did he jump?
b) How could he improve his horizontal distance?
c) Discuss the kinetic factors that influence performance.


Homework Equations



Basic linear kinematics equations as well as Impulse:

Ft = mv



The Attempt at a Solution



I think I can use linear kinematics for the two distances, but my prof said that Impulse is key to solving it. Can anyone help with answer a in particular?
 
Attachments
  • Line graph of vertical force (N) against time (ms) from 0 to 150 ms: force rises from about 500 N to a peak near 8200 N at about 21 ms, falls to about 2000 N at 40 ms, rises to about 4100 N at 80 ms, then declines to about 500 N at 150 ms.
    chart.jpg
    19.7 KB · Views: 553
The area under that graph is the impulse, but first I think you should subtract the force that simply opposes his weight. With the impulse and your equation, you can get his vertical velocity at take off (don't forget to get his mass by dividing their weight by gravity.)

He'll go furthest if he takes off at 45 degrees.

I have no idea how to interpret "horizontal velocity of take off leg". I reckon that ought to be zero otherwise he'd be slipping. Very badly worded question. You should flunk your prof.