Bionomial theorem/ question (wp)

  • Thread starter Nelo
  • Start date
  • Tags
    Theorem
As a summary,In summary, the conversation is about finding the values of k that give the same remainder when the function f(x)= x^3 + 6x^2 +kx -4 is divided by x-1 and x+2. The initial attempt at solving the problem involved setting up two equations using f(1) and f(-2), but there were mistakes made in the calculations. The correct approach was to set the remainders of f(x)/(x-1) and f(x)/(x+2) equal to each other and solve for k. This was eventually done, resulting in the correct answer of k=3.
  • #1
Nelo
215
0

Homework Statement




For what values of k does the function f(x)= x^3 + 6x^2 +kx -4 give the same remainder when divided by x-1 and x+2?

answer, however in the booklet it says the answer is 3, why is this? what did i do wrong?

Homework Equations





The Attempt at a Solution



So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k
2 = k

f(-2) = 12 -2k
2k = 12
k= 6,

I plugged 6 and 2 into the equation of f(1) and got the same (remainder of 9)

wat am i doing wrong?
 
Physics news on Phys.org
  • #2
anyone??
 
  • #3
Nelo said:
anyone??
Patience !

Please, wait at least 24 hours before bumping your thread.
 
  • #4
Nelo said:

Homework Statement

For what values of k does the function f(x)= x^3 + 6x^2 +kx -4 give the same remainder when divided by x-1 and x+2?

answer, however in the booklet it says the answer is 3, why is this? what did i do wrong?

Homework Equations


The Attempt at a Solution



So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k This says that the remainder for f(x)/(x-1) is k - 2 .
2 = k Why do this step?

f(-2) = 12 -2k This says that the remainder for f(x)/(x+2) is 12 -2k .
2k = 12
k= 6,

I plugged 6 and 2 into the equation of f(1) and got the same (remainder of 9)

what am i doing wrong?

What does the remainder theorem say?

Set the two remainders equal to each other. Solve for k.
 
  • #5
wat? like.. 6k = 2?

6/2 = 3
k=3?
 
  • #6
Nelo said:
So.. i set up two equations one using f(1) and one using f(-2)

f(1)= 1 + 6 + 1k -4
f(1) = -2 +k
1 + 6 - 4 = -2?

2 = k

f(-2) = 12 -2k
2k = 12
k= 6,
Where did the f(1) and f(-2) go? This makes no sense. If you're supposed to get the same remainder when dividing by x - 1 and x + 2, then that means that
f(1) = f(-2).

And can you also please double check your work before submitting your post?
 
  • #7
f(1)= 1 + 6 + 1k -4
f(1) = 7-4+1k
f(1) = 3+k
-3=k

f(-2) = (-2)^3 + 6(-2)^2 + k(-2) -4
f(-2) = 12 -2k
2k = 12
k= 6

?? what do i do now
 
  • #8
Nelo said:
f(1)= 1 + 6 + 1k -4
f(1) = 7-4+1k
f(1) = 3+k
-3=k
Again, why are you making the f(1) disappear? DON'T DO THAT! :mad:

You say
f(1) = 3 + k
and
f(-2) = 12 - 2k.

Since the remainders are supposed to be equal,
f(1) = f(-2)
so substitute with the right-hand-side of the two previous equations.
 
  • #9
I don't get it... substitute something that's not a full equation into the right hand side of the prev 2 eq? doesn't something have to = k inorder for me to sub it into another equation..?

How do i substitute dat
 
  • #10
Nelo said:
I don't get it... substitute something that's not a full equation into the right hand side of the prev 2 eq? doesn't something have to = k inorder for me to sub it into another equation..?

How do i substitute dat
f(1) = f(-2)
Instead of f(1), write what it equaled to.
Instead of f(-2), write what it equaled to.
That's what I meant by substituting.
 
  • #11
f(1) = 3 + k
and
f(-2) = 12 - 2k.


3+k = 12-2k
-9 = -3k
k= 3 ...

I see, thanks :P
 
  • #12
That's exactly what I suggested you do back in post #4 .
 
  • #13
gl bk
 

1. What is the binomial theorem?

The binomial theorem is a mathematical formula that allows us to expand binomial expressions raised to any positive integer power. It is written as (a + b)^n = Σ(n,k)a^(n-k)b^k, where n is the power, a and b are the binomial terms, and k is the index of summation.

2. Who discovered the binomial theorem?

The binomial theorem was first discovered by the Chinese mathematician Yang Hui in the 13th century. It was later independently discovered and popularized in Europe by Isaac Newton in the 17th century.

3. What is the purpose of the binomial theorem?

The binomial theorem is used to simplify and solve problems involving binomial expressions raised to a power. It can also be used to find coefficients, probabilities, and patterns in binomial expansions.

4. What are some real-life applications of the binomial theorem?

The binomial theorem has many real-life applications, such as in statistics, genetics, and finance. It is used to calculate probabilities in gambling and genetics, and to model the growth of investments in finance.

5. How is the binomial theorem related to Pascal's triangle?

Pascal's triangle is a triangular array of numbers that can be used to expand binomial expressions using the binomial theorem. The coefficients in each row of Pascal's triangle correspond to the coefficients in the binomial expansion of (a + b)^n. This relationship makes it easier to calculate binomial expansions for larger powers.

Similar threads

  • Precalculus Mathematics Homework Help
Replies
6
Views
692
  • Precalculus Mathematics Homework Help
Replies
4
Views
938
  • Precalculus Mathematics Homework Help
Replies
1
Views
1K
  • Precalculus Mathematics Homework Help
Replies
2
Views
512
  • Precalculus Mathematics Homework Help
Replies
6
Views
535
  • Precalculus Mathematics Homework Help
Replies
21
Views
623
  • Precalculus Mathematics Homework Help
Replies
3
Views
846
  • Precalculus Mathematics Homework Help
Replies
12
Views
480
  • Precalculus Mathematics Homework Help
Replies
7
Views
2K
  • Precalculus Mathematics Homework Help
Replies
3
Views
2K
Back
Top