Black body radiation and the derivation of Stefan Boltzman

Click For Summary

Homework Help Overview

The discussion revolves around the mathematical derivation related to black body radiation and the Stefan-Boltzmann law, specifically focusing on the variable substitution in an integral involving wavelength.

Discussion Character

  • Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are exploring the relationship between differentials in the context of variable substitution, questioning the correctness of the substitution from dλ to dx. There is a specific focus on deriving the correct expression for dλ in terms of dx.

Discussion Status

Participants are actively engaging in clarifying the mathematical relationships involved in the derivation. Some have provided expressions and are seeking confirmation or correction from others, indicating a collaborative effort to understand the derivation process.

Contextual Notes

There appears to be a focus on the assumptions made regarding the relationship between λ and x, with specific constants involved in the discussion. The nature of the problem suggests that participants are working within the constraints of a homework assignment, which may limit the information available for discussion.

dcarmichael
Messages
17
Reaction score
2
Homework Statement
The total intensity i(t) radiated from a blackbody is given by the integral from 0 to infinity of all wavelengths of the Planck distribution.But I keep seem to be getting the wrong answer. Could someone point out where I'm going wrong
Relevant Equations
Let l=lambda I(l,T)=(2Pihc^2)/l^5 *1/(e^(hc/lkT)-1)
20191102_144741.jpg
20191102_144734.jpg
 
Physics news on Phys.org
What did you replace dλ with when converting to x as the variable of integration?
 
haruspex said:
What did you replace dλ with when converting to x as the variable of integration?
I didnt indicate it but dλ is replaced with dx since x is new variable of integration
 
dcarmichael said:
I didnt indicate it but dλ is replaced with dx since x is new variable of integration
##d\lambda \neq dx##

Note that you can write ##\lambda = \large \frac{a}{x}##, where ##a## is a constant. Taking the differential of both sides of this relation, you should get ##d\lambda = \boxed ?\, dx##. What goes inside the box?
 
TSny said:
##d\lambda \neq dx##

Note that you can write ##\lambda = \large \frac{a}{x}##, where ##a## is a constant. Taking the differential of both sides of this relation, you should get ##d\lambda = \boxed ?\, dx##. What goes inside the box?
dλ= -(a/x^2)dx
 
Ok. Go for it.
 

Similar threads

Replies
5
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
7
Views
2K
  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K