Black body radiation, Plancks' Law question?

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SUMMARY

The discussion centers on calculating the diameter of a cylinder that emits 100W at a temperature of 2000K, assuming it behaves as a perfect black body. The user employs Planck's Law and Wien's Displacement Law to derive the peak frequency of radiation and attempts to formulate an equation involving the surface area and solid angle of the cylinder. The user expresses difficulty in solving for the radius and seeks clarification on the necessity of the Stefan-Boltzmann Law in this context.

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Homework Statement



A cylinder of length 0.02m emits 100W and is at 2000K. It is a perfect black body. What is it's diameter?


Homework Equations



Planck's Law:

B(λ,T) =

http://en.wikipedia.org/wiki/Planck's_law

solid radian = A/r^2 (not sure if needed or not)


The Attempt at a Solution




surface area = 0.02 x 2 pi r + 2 pi r^2

solid radians of the cylinder = (pi r^2) / (r^2 + 0.01^2)

r is radius of the cylinder

frequency of peak radiation = 2.07 x 10^14

(I used Wien's displacement law to get the peak frequency)

B x surface area x solid radians x frequency = 100W

(I'm using dimensional analysis here, not really sure what's going on)

100 = 9.104 x 10^-10 x (0.04 pi r + 2 pi r^2) x (pi r^2)/(r^2 x 10^-6) x 2.07 x 10^14

which rearranges to...

5.303 x 10^-14 (r^2 + 1x10^-6) = 0.04 (pi)^2 r^3 + 2 (pi)^2 r^4

I can't solve for r :(

any help or explanation is much appreciated
 
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Don't you have to use the Stefan-Boltzmann law ??
 

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