Block floating in water - Oil is added

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SUMMARY

The discussion focuses on the physics problem of a wooden block floating in water, initially submerged at 75% before oil is added. The density of the oil is specified as 715 kg/m³, and the solution involves applying Archimedes' principle and Newton's second law to determine the new fraction of the block submerged after the oil is poured. The density of the wood is calculated using the known density of water, which is 1000 kg/m³. This foundational understanding allows for accurate calculations regarding buoyancy and displacement.

PREREQUISITES
  • Understanding of Archimedes' principle
  • Knowledge of Newton's second law of motion
  • Familiarity with density calculations
  • Basic principles of buoyancy
NEXT STEPS
  • Calculate the density of the wooden block using the initial submerged fraction
  • Apply Archimedes' principle to find the new submerged fraction after oil is added
  • Explore the effects of different oil densities on buoyancy
  • Investigate the relationship between fluid density and buoyant force
USEFUL FOR

Students studying physics, particularly those focusing on fluid mechanics and buoyancy, as well as educators looking for practical examples of Archimedes' principle in action.

emenos
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Homework Statement


A block of wood floats on water. A layer of oil is now poured on top of the water to a depth that more than covers the block.If 75% of the wood is submerged in water before the oil is added, find the fraction submerged when oil with a density of 715 kg/m3 covers the block. (Do not neglect the buoyant force of air before the oil is added.)



Homework Equations





The Attempt at a Solution

 
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Hey emenos,
The fraction of the block floating initially is given. Get the density of the block from this assuming Dwater=1000kg/m^3. Once you get the density use archimedes principle and Newton's 2nd law to get the required fraction.
 

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