Block on an inclined plane between two strings

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SUMMARY

A block of mass 0.25 kg rests on a frictionless inclined plane at an angle of 30 degrees, secured by two springs. The top spring has a spring constant that is twice that of the bottom spring. When the top spring is stretched by 0.082 m and the bottom spring is compressed by the same amount, the relationship between gravitational force and spring forces can be expressed as mgsin(θ) = 3k, where k is the spring constant of the bottom spring. To find k, one must equate the potential energy stored in the springs with the work done by gravitational force on the block.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with Hooke's Law (F = -k(X-Xo))
  • Knowledge of potential energy concepts
  • Ability to draw and interpret free body diagrams
NEXT STEPS
  • Calculate the potential energy stored in the springs using the formula U = 1/2 k x^2
  • Determine the work done by gravitational force on the block using W = mgh
  • Explore the relationship between spring constants in series and parallel configurations
  • Study the dynamics of blocks on inclined planes with multiple forces acting on them
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Students and professionals in physics, mechanical engineering, and anyone studying dynamics involving inclined planes and spring systems.

paulius005
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Block of mass M between two strings on incline?
A block of mass M rests on a frictionless inclined plane of angle θ as shown in the diagram below. Two springs of equal length are connected to the block and to two posts as shown. The separation between the posts is equal to the sum of relaxed lengths of the springs and the length of the block.

Suppose the top spring is stretched from its relaxed length by an amount δx = 0.082 m and the bottom string is compressed by the same amount.. If the spring constant of the top spring is twice that of the bottom spring and M = 0.25 kg and θ = 30o, what is k, the spring constant of the bottom spring?

http://i43.tinypic.com/2z4bcaw.gif

link to image

Now I know that I may need to use F = -k(X-Xo) and draw a free body diagram.

After drawing the free body diagram I get that mgsin(theta)=3k since there is one spring with spring constant k and another with 2k. I am not sure how to put the stretched length into all that though. Or since -k(X-Xo) = the vector some of the forces does that mean that mgsin(theta) = 3(-k(X-Xo)). Just a bit confused.
 
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Hi paulius005, welcome to PF.
What is the potential energy stored in the springs?
What is the work done by gravitational force on the block?
Equate them to find k.
 

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