Block sliding down incline at constant velocity with friction

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crosbykins
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URGENT physics find angle of inclined plane! help!?

Homework Statement



A block slides down an inclined plane at a constant velocity of 0.14m/s. The coefficient of kinetic friction is 0.45. What is the angle of inclination?



Homework Equations


Fnetx = Fk -mgsintheta
Fnety = FN -mgcostheta


The Attempt at a Solution



FN-mgcosΘ = 0
FN =mgcosΘ

FN µK –mgsinΘ =0
FN = mgsinΘ/.45

mgcosΘ = mgsinΘ/.45
.45 = mgsinΘ/ mgcosΘ
.45 = tanΘ
tan-1.45 =Θ
24⁰ =Θ

Is this correct? What I don't understand is that shouldn't Fnetx include an Fapp? The question doesn't give a value for Fapp so I don't how you would use it to find the answer.
 
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hi crosbykins! :smile:

(have a smaller theta: θ and try using the X2 icon just above the Reply box :wink:)
crosbykins said:
What I don't understand is that shouldn't Fnetx include an Fapp? The question doesn't give a value for Fapp so I don't how you would use it to find the answer.

yes that looks fine :smile:

i'm not sure what you mean by Fapp …

the block is simply sliding under gravity (any force that pushed it to get it started has been removed)