Block sliding down incline shaped as circle

  • Thread starter qtbuy07
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  • #1
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Homework Statement


A 2-kilogram block is released from rest at the top of a curved incline in the shape of a quarter circle of radius R. The block then slides onto a horizontal plane where it finally comes to rest 8 meters from the beginning of the plane. The curved incline is frictionless, but there is an 8 newton force of friction on the block while it slides horizontally. Assume g=10N/kg
A) Determine the magnitude of the acceleration of the block while it slides along the horizontal plane.
B) what time elapses while the block is sliding horizontally
C)Calculate the radius of the incline in meters




Homework Equations


F/m=a
t= 2(delta)x/a (squared)



The Attempt at a Solution


a- 8N/2kg=4m/s^2
b- T=2(8m)/4m/s^2 (squared)= 2 sec
c-???
 

Answers and Replies

  • #2
2,685
22


a) OK

b) I don't know what equation you are using there, but it's wrong and doesn't give the answer of 2 seconds. 2 seconds is the right answer (as per my equation below), but your equation gives an answer of 1 second or 16 seconds depending on how you did it (see example below).

t = 2(8)/42 = 16/16 = 1
or you squared everything
t = (2(8)/4)2 = (16/4)2 = 16
Both of these are wrong. It appears you have rearranged the below equation incorrectly.

You want to use the SUVAT equations of motion. In this case: s=vt+0.5at2, where s = distance travelled (8m), v = final speed (0m/s) and a = acceleration (from part a).

Substitute in the values and you end up with s=0.5at2. Rearrange and that will give you the travel time.

Based on my SUVAT equation above, yours should be: Sqrt(2s/a) = t.
 

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