- #1

fobbz

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## Homework Statement

A rectangular block 3m high and 1.8m wide weighing in at 7600N is pushed with a force 20.5° to the height of the block 1.6m from the bottom of the block.

Calculate the Force Required to tip over this block.

## Homework Equations

Torque = perpendicular force x distance or force x perpendicular distance

## The Attempt at a Solution

Firstly, I make a free body diagram of the block.

N force up

mg force down

F 69.5° [N o E]

Secondly, I write my ƩTorque eq, using the pivot point where the box will tip on an angle. I will call this P.

Ʃτ

_{p}= 0

(0.9)mg = (Fsin69.5)(1.6)

F = 4564.0 N