MHB Bobby's question at Yahoo Questions regarding bacterial growth

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A bacterium doubles in population every 6 hours and starts at 1 cm². The population can be modeled by the equation P(t) = P_0 * 2^(t/6). To determine when the bacterium fills a Petri dish with a radius of 2 cm, the area equation A(t) = A_0 * 2^(t/6) is used, leading to A(t) = 2^(t/6). Solving the equation 2^(t/6) = 4π gives a time of approximately 21.9 hours for the bacterium to fill the dish.
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Here is the question:

Differential Equation Problem?

A bacterium doubles in population every 6 hours. If the area that the bacterium is spread
over is proportional to its population (that is, if the population density remains constant),
and begins at 1 cm2, how long will it take the bacterium to fill the entire area of a Petri dish
of radius 2cm?

I have posted a link there to this thread so the OP can view my work.
 
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Hello Bobby,

We don't need to solve an ODE, we can see from the given information that the population of the bacteria must be given by:

$$P(t)=P_02^{\frac{t}{6}}$$

Now, since the population density remains constant, we have:

$$A(t)=A_02^{\frac{t}{6}}$$

And we are told $$A_0=1\text{ cm}^2$$ and so in square cm, we may write:

$$A(t)=2^{\frac{t}{6}}$$

Now, to find when the culture fills the dish, we may write:

$$2^{\frac{t}{6}}=\pi(2)^2=4\pi$$

Taking the natural log of both sides, we obtain:

$$\frac{t}{6}\ln(2)=\ln(4\pi)$$

Solve for $t$:

$$t=\frac{4\ln(4\pi)}{\ln(2)}\approx21.9089767768339$$

Hence it will take about 21.9 hours for the culture to fill the dish.
 
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