Boiling and Freezing Points of Solutions

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SUMMARY

The aqueous solution with the lowest freezing point among the options provided is 0.008m MgCl2. This conclusion is based on the colligative properties of solutions, where the freezing point depression is influenced by the number of dissolved particles. The Van 't Hoff factor indicates that MgCl2 dissociates into three ions (one Mg2+ and two Cl-), resulting in a greater effect on freezing point depression compared to the other solutions, which only dissociate into two ions or remain as non-electrolytes.

PREREQUISITES
  • Understanding of colligative properties in solutions
  • Knowledge of Van 't Hoff factor
  • Familiarity with ionic and non-ionic compounds
  • Basic principles of freezing point depression
NEXT STEPS
  • Research the Van 't Hoff factor and its application in colligative properties
  • Study the concept of freezing point depression in detail
  • Explore the differences between electrolytes and non-electrolytes
  • Learn about the calculation of freezing point depression using molality
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Chemistry students, educators, and professionals involved in physical chemistry and solution chemistry will benefit from this discussion.

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Homework Statement



The aqueous solution with the lowest freezing point of the following group is:

1) 0.01m MgSO4
2) 0.01m NaCl
3) 0.01m CH3CH2OH
4) 0.008m MgCl2
5) all equal

Homework Equations



Solutions have lower freezing points and higher boiling points than their solvents.

CH3CH2OH is a non-electrolyte. It will not dissolve.

The Attempt at a Solution



I don't know exactly how to estimate the freezing point. I'm assuming it has something to do with the concentration of the ions. In that case it seems as if 0.008m of MgCl2 would dissolve into the most ions (Mg2+ and 2Cl-). Although it has a lower molarity, it dissolves to form one Mg2+ and 2Cl-, unlike all the other 0.01m solutions, which only dissolve to form one cation and one anion.
 
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You are on the right track. Google for Van 't Hoff factor.
 
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