Question: When alpha particles, having kinetic energy 3.0000 MeV bombard nitrogen-14 nuclei, oxygen-17 forms and the reaction releases a proton. Calculate the kinetic energy shared by the reaction products. Nitrogen-14 = 14.000307 amu Helium-4 = 4.00260 amu Oxygen-17 = 16.99913 amu Proton = 1.00727 amu 1 amu = 931 MeV Attempt at question: I cannot derive the textbook answer (1.65 MeV). I found the increase in mass to be 0.00073 amu which equals 0.67963 MeV. I subtract this from 3.0000 MeV, but I got instead 2.32037 MeV. Does anyone know how to obtain the textbook solution? Thanks a lot.