# Bombardment of Nitrogen-14 with an alpha particle

Question:
When alpha particles, having kinetic energy 3.0000 MeV bombard nitrogen-14 nuclei, oxygen-17 forms and the reaction releases a proton. Calculate the kinetic energy shared by the reaction products.
Nitrogen-14 = 14.000307 amu
Helium-4 = 4.00260 amu
Oxygen-17 = 16.99913 amu
Proton = 1.00727 amu
1 amu = 931 MeV

Attempt at question:
I cannot derive the textbook answer (1.65 MeV). I found the increase in mass to be 0.00073 amu which equals 0.67963 MeV. I subtract this from 3.0000 MeV, but I got instead 2.32037 MeV. Does anyone know how to obtain the textbook solution? Thanks a lot.

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Hi,
If you want to calculate the q-value of the reaction you must have a better precision in your atomic mass (see https://www-nds.iaea.org/amdc/ame2016/mass16.txt)
If you take this mass number you will have Q=-1.192 MeV. Q <0 because the reaction is endothermic (threshold reaction)
PSR

agent5514
mfb
Mentor
You should use the isotopic mass of 1H, otherwise you miss an electron (the other isotope masses are with electrons).

If I calculate it, the reaction is not even possible.

Edit: You have a typo in the nitrogen mass, there is one more zero than it should be.

I get 1.81 MeV.

agent5514