Boundary Conditions for Hydrogen Schrodinger Equation

Click For Summary
SUMMARY

The boundary conditions for solving the hydrogen Schrödinger equation, specifically for hydrogen-1, require the wave function to approach zero as the radius approaches infinity, ensuring square integrability. Additionally, the wave function must be finite, meaning the integral of Psi*Psi must be square integrable. The method of separation of variables imposes conditions that the spatial components of the solution are time-invariant, and the wave functions in polar coordinates must be orthogonal and normal. These conditions are crucial for deriving accurate energy eigenvalues and quantum numbers for the hydrogen atom.

PREREQUISITES
  • Understanding of the Schrödinger equation
  • Knowledge of quantum mechanics concepts such as wave functions
  • Familiarity with boundary conditions in differential equations
  • Proficiency in polar coordinates and their application in quantum mechanics
NEXT STEPS
  • Research the normalization conditions for wave functions in quantum mechanics
  • Study the method of separation of variables in solving differential equations
  • Learn about square integrability and its implications in quantum mechanics
  • Explore the differences in boundary conditions across various coordinate systems
USEFUL FOR

Students and professionals in quantum mechanics, physicists focusing on atomic structure, and anyone involved in theoretical physics or mathematical physics.

space-time
Messages
218
Reaction score
4
If I am trying to derive the energy eigenvalues and quantum numbers for the hydrogen atom (basic hydrogen-1), I obviously need to solve the hydrogen Schrödinger equation and account for some boundary conditions. However, no website ever gives me the boundary conditions. What would be the boundary conditions for the hydrogen atom?
 
Physics news on Phys.org
The usual thing is to have the wave function go to zero as radius goes to infinity. Is that enough?
 
DEvens said:
The usual thing is to have the wave function go to zero as radius goes to infinity. Is that enough?
Integral of Psi*Psi needs to be finite (square integrable). You can have a function go to zero as r->inf. that would not be square integrable.
 
The usual method of separation of variables imposes a 'boundary' condition that the spatial components of the solution are independent of time - i.e. time-invariant.
This may be excessive, as the requirement that the final wave function be square-integrable permits wave functions that are periodic with finite integrability.
The other boundary conditions also imposed by the method are that the components of the wave function in polar coordinates are orthogonal and normal.
The polar coordinates themselves are part of this, in that in other coordinate systems (rectilinear, cylindrical) the wave functions are NOTsquare-integrable.
 
Quantum Defect said:
Integral of Psi*Psi needs to be finite (square integrable). You can have a function go to zero as r->inf. that would not be square integrable.

That is normalization, not boundary condition.
 
Quantum Defect said:
Integral of Psi*Psi needs to be finite (square integrable). You can have a function go to zero as r->inf. that would not be square integrable.
And you can have square integrable functions which don't go to 0 when their argument goes to infinity.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K