Bowling Ball Rise: Find Speed at Top w/Conservation of Energy

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Homework Help Overview

The problem involves a bowling ball rising vertically and requires determining its speed at the top of the rise using principles of conservation of energy. The scenario includes a height of 0.662 m and an initial speed of 3.70 m/s at the bottom of the rise.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of conservation of energy, questioning how to relate kinetic and potential energy. There is uncertainty regarding the mass of the ball and its relevance to the calculations. Some participants attempt to set kinetic energy equal to potential energy but express confusion over the correctness of their results.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the conservation of energy equation. Some guidance has been offered regarding the relationship between initial and final energies, but there is no consensus on the correct approach or solution yet.

Contextual Notes

Participants note the absence of the ball's mass in the problem statement, which raises questions about its impact on the calculations. There is also mention of incorrect answers being derived from the attempted calculations.

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Homework Statement



A bowling ball encounters a h = 0.662 m vertical rise on the way back to the ball rack, as the figure below illustrates.

Ignore frictional losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 3.70 m/s at the bottom of the rise. Find the translational speed at the top.

Homework Equations



KE= 1/2mv^2

U=mgh

Conservation of energy and momentum?


The Attempt at a Solution


I tried basic conservation of energy but that didn't really work out. I'm not sure where to start on this one since it doesn't give the mass of the ball. Though that probably cancels out anyway. When I set KE = U the answer is incorrect. I'm not sure on what else I can do.
 
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The initial kinetic energy is not equal to the change in potential energy. The initial energy is equal to the change in potential energy plus the final kinetic energy.
(KE + U)_1 = (KE + U)_2
 
So:

1/2mvi2=mgh + 1/2mvf2?


When I plug in the values for this the answer is incorrect as well.
 
The answer is not 0.837 m/s?
 

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