Box Acceleration with Given Force and Coefficient of Friction

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SUMMARY

The discussion focuses on calculating the acceleration of a 15.0 kg box being pushed with a force of 72.0 N at an angle of 65 degrees from the horizontal, with a coefficient of friction of 0.12. The net force acting on the box can be determined using the equation Fnet = ma, where 'm' is the mass and 'a' is the acceleration. A force diagram is essential for visualizing the forces involved, including friction and the applied force. The solution requires applying Newton's second law and understanding the components of the forces acting on the box.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of force diagrams and vector components
  • Familiarity with the concept of friction and the coefficient of friction
  • Basic algebra for solving equations
NEXT STEPS
  • Learn how to draw and interpret force diagrams in physics problems
  • Study the effects of friction on motion, including static and kinetic friction
  • Explore vector decomposition to resolve forces into horizontal and vertical components
  • Practice solving problems involving Newton's laws of motion
USEFUL FOR

Students studying physics, particularly those tackling mechanics problems involving forces and motion, as well as educators looking for examples of real-world applications of Newton's laws.

RajNijhar
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Homework Statement


A person is pushing a 15.0kg box on the ground with a force of 72.0N 65Degrees from the horizontal. if the coefficient of friction is0.12 what will be the acceleration of the box?


Homework Equations


Fnet=ma
there's other formulas but i don't have my data sheet :(


The Attempt at a Solution


soo lost don't even know where to start pelase help
 
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That is the only major equation you need to solve the problem.
 
Draw a force diagram , showing all forces acting on the box.

p.s. welcome to Physics Forums, everybody. :smile:
 

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