Friction problem (pushing a box)

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Homework Help Overview

The discussion revolves around a physics problem involving a person pushing a box with a specified net external force and frictional force. Participants are trying to determine the correct acceleration of the box based on the given forces.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants are analyzing two different attempts to calculate the acceleration, questioning the relevance of the friction force in the context of the net force provided. There is uncertainty about whether the friction force should be included in the calculations.

Discussion Status

Some participants have expressed confusion regarding the problem's setup, particularly about the role of friction in determining the acceleration. There is a recognition that the first solution aligns with the net force given, while the second solution is viewed as potentially incorrect. The discussion is ongoing, with participants seeking clarity on the problem's intent.

Contextual Notes

Participants note the ambiguity in the problem statement regarding the inclusion of friction as an external force, which may affect their interpretations and calculations.

Alyona
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Homework Statement


A person is pushing a box. The net external force on the 60 kg box is stated to be 90 N. If the force of friction opposing the motion is 30 N, what is the acceleration of the box?

Homework Equations


This seems to be a pretty easy, straightforward problem, but I'm confused. Is the first or second solution correct?

The Attempt at a Solution


Fnet = F - f = ma
90 N = F - 30 N = (60 kg)a
a = 90 N / 60 kg = 1.5 m/s2

Fnet= F - f = ma
90 N = F - 30 N
F = 120 N
F = ma
120 N = (60 kg)a
a = 120 N / 60 kg = 2.0 m/s2
 
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Alyona said:

Homework Statement


A person is pushing a box. The net external force on the 60 kg box is stated to be 90 N. If the force of friction opposing the motion is 30 N, what is the acceleration of the box?

Homework Equations


This seems to be a pretty easy, straightforward problem, but I'm confused. Is the first or second solution correct?

The Attempt at a Solution


Fnet = F - f = ma
90 N = F - 30 N = (60 kg)a
a = 90 N / 60 kg = 1.5 m/s2

Fnet= F - f = ma
90 N = F - 30 N
F = 120 N
F = ma
120 N = (60 kg)a
a = 120 N / 60 kg = 2.0 m/s2
I am confused, too. The problem statement says the net external force is 90N and then introduces another external force - friction. Friction certainly an external force - it is a force the surface exerts on the box. So I think your first answer is correct given the way the problem is stated, but I am not sure that was the intent of the person who wrote the problem.
Edit: I do not think your second answer is correct - that answer ignores the force of friction on box.
 
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Yes, it's confusing. If you don't need the force of friction to solve the problem, since the net force was given, why put it in the problem then? I think the first solution is correct, but I'm not sure.
 
tnich said:
Edit: I do not think your second answer is correct - that answer ignores the force of friction on box.

Ohh, I get it now, thank you for your help!
 

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