Acceleration of object with friction: Homework help

In summary, the minimum force required to start the box sliding from rest is 343 N. After the box starts sliding, the person must continue to apply a force equal to the kinetic friction force of 245 N to maintain a constant velocity. Therefore, the acceleration of the box is 0 m/s^2. This is because the net force on the box is now zero, as the kinetic friction force balances out the applied force.
  • #1
APphysicsSenior
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A 50 kg box rests on the floor. The coefficients of static and kinetic friction are 0.70 and 0.50, respectively.
a.) What is the minimum force required to start the box sliding from rest?
b.) After the box starts sliding, the person continues to maintain that force. What is the acceleration of the box?

Homework Equations

: μ=Ff/mg Fnet=ma[/B]3. I solved part A by using the force of static friction and my answer was 343 N, but I can't figure out part B. I figured since the net force on my force diagram was zero and the box is sliding at a constant velocity, that the acceleration would be zero, but that isn't correct. Any ideas?
 
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  • #2
APphysicsSenior said:
I figured since the net force on my force diagram was zero
The net force is zero only before it begins sliding. Once it starts sliding, what happens to the friction force?
 

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