Boxcar accelerating up incline, pendulum suspended within

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SUMMARY

The discussion centers on calculating the acceleration of a boxcar traveling up a 9.85-degree incline, with a pendulum suspended inside at an angle of 24.05 degrees from the perpendicular. The user initially derived the equation a = tan(14.2) g based on the forces acting on the pendulum, but this solution was identified as incorrect. The key insight provided is that the acceleration should be considered along the direction of the incline rather than purely horizontal.

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lizzyb
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This seems like an easy problem but my answer is incorrect.

Imagine a boxcar traveling up a 9.85 degree slope with constant acceleration a. In the boxcar is a pendulum that hangs 24.05 degree from the perpendicular to the boxcar's ceiling and floor. Find the acceleration.

It seems to me that the pendulum is off 14.2 degrees from vertical, and so we have:

T sin(24.05 - 9.85) = m a : Fx
T cos(24.05 - 9.85) - mg = 0 : Fy

So solving for a we have a = tan(14.2) g

Yet this is not the correct solution. Any ideas? thanx.
 
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You assumed that the acceleration is in the x-direction (horizontal). Maybe the given acceleration is along the direction of the incline.
 

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