Braindead - Simple Physics Help

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Homework Help Overview

The problem involves calculating the average speed of a car traveling between two points, A and B, with different speeds for each leg of the journey. The original poster attempts to express the average speed as a function of the distance between the two points.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the definition of average speed in this context, emphasizing that it involves total distance divided by total time rather than a simple arithmetic mean. There are attempts to express the total time for the journey in terms of distance and speed, with some participants questioning how to formulate the average speed as a function of distance.

Discussion Status

Participants are actively engaging with the problem, providing insights into how to approach the calculation of average speed. Some guidance has been offered regarding the relationship between distance, speed, and time, and there is a recognition of the need to express the average speed in terms of distance. Multiple interpretations of the problem are being explored.

Contextual Notes

The original poster notes that this problem is for a Pre-Calculus course, indicating a potential gap in the application of concepts from previous physics coursework. There is also a mention of the need to express the function specifically in terms of distance.

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Homework Statement



A car averages 80 km/h traveling from A to B, and then on the return trip the car averages 60 km/h from B to A. Write the average speed of the car, V, as a function of x, where x is the distance from A to B.


Homework Equations



Not sure what to use.


The Attempt at a Solution



Vavg = [80 km/h(x) + 60 km(x)]/2

Obviously it's wrong =/
 
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you must understand that the average speed in this context means the total distance divided by the time taken to cover that distance.
the average speed here doesn't mean the arithmetic mean that we usually learn in mathematics.
 
The question doesn't provide the time though, and the function needs to be written as a function of the distance.
 
speed = distance/time
you know the average speed for the go and return journeys and the distance is the same. so you can express the TOTAL time to cover both the journeys in term of the distance x.
 
Last edited:
speed= distance/time=> time= distance/speed

Of course, the total distance is 2x.
 
I have to express it as V(x) though so I have to express Speed in terms of distance. This is for Pre-Calc, btw. I did all the mechanics things in AP Physics but this is unrelated, right? I've been trying for a while but I still can't get it =/..

I know I can express it in terms of time as T = ((x)/(80kph)) + ((x)/60kph))..
 
megaforcetkd said:
I have to express it as V(x) though so I have to express Speed in terms of distance. This is for Pre-Calc, btw. I did all the mechanics things in AP Physics but this is unrelated, right? I've been trying for a while but I still can't get it =/..

I know I can express it in terms of time as T = ((x)/(80kph)) + ((x)/60kph))..

That's right. That's the total time for the trip. What's the total distance in terms of x?
 
2x = ((x)/(80kph)) + ((x)/60kph))(speed).. what do i put for speed?
 
megaforcetkd said:
2x = ((x)/(80kph)) + ((x)/60kph))(speed).. what do i put for speed?

Solve this expression for speed.
 
  • #10
OH so...

Vavg = (2x)/((x)/(80kph)) + ((x)/60kph)).
 
  • #11
megaforcetkd said:
OH so...

Vavg = (2x)/((x)/(80kph)) + ((x)/60kph)).

Yup. That's right. You can simplify.
 
  • #12
AHHHH! Ok thanks :D. I guess I just wasn't thinking =/ We did this first day of AP Physics.
 
  • #13
megaforcetkd said:
AHHHH! Ok thanks :D. I guess I just wasn't thinking =/ We did this first day of AP Physics.

:smile: What did you get as the final answer?
 
  • #14
68.57 km/h
 
  • #15
megaforcetkd said:
68.57 km/h

Yup, that's the answer! Excellent!
 
  • #16
YAY! Thanks for the help. Haha you can expect a lot of me though once we start getting into complicated stuff in AP Physics QQ.
 

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