What are the average speed formulas needed to solve this problem?

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Homework Help Overview

The problem involves calculating the average speed of a car that travels a distance at two different speeds: 40 km/h and 60 km/h. The original poster expresses difficulty in arriving at the correct average speed, repeatedly obtaining 50 km/h, and notes the lack of time or distance information.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to calculate time for each leg of the trip based on the given speeds and the same distance traveled. There are suggestions to define the distance as a variable (D) to facilitate calculations. Some participants express uncertainty about their knowledge and seek further clarification.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and offering guidance on how to approach it using variables. There is no explicit consensus on a solution, and some participants emphasize the forum's guidelines against providing complete solutions.

Contextual Notes

Participants note the importance of working with variables when certain information is missing, and there are reminders about the forum's rules regarding homework help.

Ehsan Abedian
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Homework Statement


A car is moving in a road and its average speed is 40 km/h. Then it moves back in that road by 60 km/h speed. What is the average speed of this car? ( The answer is not 50 km/h )

Homework Equations


Average speed= d/t

The Attempt at a Solution



I can't solve this. I get 50 km/h every time. I do this: (60+40)/2
Because I don't have time or distance.

Please Help
Thanks
 
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Ehsan Abedian said:

Homework Statement


A car is moving in a road and its average speed is 40 km/h. Then it moves back in that road by 60 km/h speed. What is the average speed of this car? ( The answer is not 50 km/h )

Homework Equations


Average speed= d/t

The Attempt at a Solution



I can't solve this. I get 50 km/h every time. I do this: (60+40)/2
Because I don't have time or distance.
But you know that it goes the same distance for each part of the trip.
Let D = the distance for each leg of the trip.
Calculate the time it takes for the first leg at 40 km/hr.
Calculate the time it takes for the second leg at 60 km/hr.
You now have enough information to calculate the average speed for both legs.

BTW, in future threads, try to come up with a better thread title. "I can't solve this problem" is NOT a good thread title. I changed the title for you to something more informative.
 
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Mark44 said:
But you know that it goes the same distance for each part of the trip.
Let D = the distance for each leg of the trip.
Calculate the time it takes for the first leg at 40 km/hr.
Calculate the time it takes for the second leg at 60 km/hr.
You now have enough information to calculate the average speed for both legs.

BTW, in future threads, try to come up with a better thread title. "I can't solve this problem" is NOT a good thread title. I changed the title for you to something more informative.

Thanks

But I can't calculate the time. Maybe I don't have enough knowledge.

Can you show me the solution?

Thanks a lot
 
Ehsan Abedian said:
But I can't calculate the time. Maybe I don't have enough knowledge.
When there is something in a problem that you don't know but think you need, try replacing it with a variable (i.e. an "unknown"). Then proceed to work out what you want using that variable in place of the unknown quantity. If it turns out that you didn't need it after all, it will cancel out (disappear) along the way to your solution. Working with variables and applying the rules of algebra to solve problems is an important skill to master.

Hint: For this problem, try letting the length of the road be represented by the variable D.
 
Ehsan Abedian said:
But I can't calculate the time. Maybe I don't have enough knowledge.
For each leg of the trip you have the distance (D) and the rate (40 km/hr for the first leg and 60 km/hr for the second leg). That's enough information to get an expression for the time of each leg.
Ehsan Abedian said:
Can you show me the solution?
No, that's not how it works here. The rules of this forum don't allow us to work a problem for you. See https://www.physicsforums.com/threads/physics-forums-global-guidelines.414380/ (under Homework Guidelines).
 
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