Bruno Tolentino
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I know several math formulas, like which I will write below.
\int_{x_0}^{x_1} f(x) dx
\frac{\int_{x_0}^{x_1} f(x) dx}{x_1-x_0}
\frac{\int_{x_0}^{x_1} f(x) dx}{2}
f(x_1) - f(x_0)
\frac{f(x_1) - f(x_0)}{x_1-x_0}
\frac{f(x_1) - f(x_0)}{2}
\frac{f(x_1) + f(x_0)}{2}
And I know too that all equations above are importants, appears with very often. But my doubt is the following:
My head is confused, are to much equations and concepts disconnected. I know that the inverse analog of derivative is the primitive, but what's the inverse analog of the arithmetic mean? If the AM of two numbers is (a+b)/2, so the analog inverse is (a-b)/2? And what's the inverse analog of (a+b+c)/3? What's the difference between the equations that I posted above!? What's the inverse analogo of each equation that I wrote above?
\int_{x_0}^{x_1} f(x) dx
\frac{\int_{x_0}^{x_1} f(x) dx}{x_1-x_0}
\frac{\int_{x_0}^{x_1} f(x) dx}{2}
f(x_1) - f(x_0)
\frac{f(x_1) - f(x_0)}{x_1-x_0}
\frac{f(x_1) - f(x_0)}{2}
\frac{f(x_1) + f(x_0)}{2}
And I know too that all equations above are importants, appears with very often. But my doubt is the following:
My head is confused, are to much equations and concepts disconnected. I know that the inverse analog of derivative is the primitive, but what's the inverse analog of the arithmetic mean? If the AM of two numbers is (a+b)/2, so the analog inverse is (a-b)/2? And what's the inverse analog of (a+b+c)/3? What's the difference between the equations that I posted above!? What's the inverse analogo of each equation that I wrote above?