Brainstorm and confusion of concepts

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SUMMARY

This discussion centers on the confusion surrounding mathematical expressions and their interpretations. The user lists several mathematical expressions related to integrals and averages, seeking to understand their inverse analogs. Key points include the clarification that none of the listed expressions are equations, as they lack equality signs. Additionally, the concept of an inverse analog for the arithmetic mean is deemed non-existent, and the distinction between expressions and equations is emphasized.

PREREQUISITES
  • Understanding of basic calculus concepts, including integrals and derivatives.
  • Familiarity with mathematical expressions versus equations.
  • Knowledge of arithmetic mean and its properties.
  • Basic understanding of function behavior and graph interpretation.
NEXT STEPS
  • Research the definitions and properties of integrals in calculus.
  • Study the concept of derivatives and their geometric interpretations.
  • Explore the differences between expressions and equations in mathematics.
  • Investigate the properties of averages and means in statistics.
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Students of mathematics, educators teaching calculus concepts, and anyone interested in clarifying mathematical terminology and expressions.

Bruno Tolentino
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I know several math formulas, like which I will write below.
\int_{x_0}^{x_1} f(x) dx
\frac{\int_{x_0}^{x_1} f(x) dx}{x_1-x_0}
\frac{\int_{x_0}^{x_1} f(x) dx}{2}
f(x_1) - f(x_0)
\frac{f(x_1) - f(x_0)}{x_1-x_0}
\frac{f(x_1) - f(x_0)}{2}
\frac{f(x_1) + f(x_0)}{2}
And I know too that all equations above are importants, appears with very often. But my doubt is the following:
My head is confused, are to much equations and concepts disconnected. I know that the inverse analog of derivative is the primitive, but what's the inverse analog of the arithmetic mean? If the AM of two numbers is (a+b)/2, so the analog inverse is (a-b)/2? And what's the inverse analog of (a+b+c)/3? What's the difference between the equations that I posted above!? What's the inverse analogo of each equation that I wrote above?
 
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Bruno Tolentino said:
I know several math formulas, like which I will write below.
\int_{x_0}^{x_1} f(x) dx
\frac{\int_{x_0}^{x_1} f(x) dx}{x_1-x_0}
\frac{\int_{x_0}^{x_1} f(x) dx}{2}
f(x_1) - f(x_0)
\frac{f(x_1) - f(x_0)}{x_1-x_0}
\frac{f(x_1) - f(x_0)}{2}
\frac{f(x_1) + f(x_0)}{2}
And I know too that all equations above are importants,
None of the above is an equation, so none would be considered a formula. They are all expressions.
Writing them as you have above is a meaningless exercise if you don't know what they represent.
##\int_{x_0}^{x_1} f(x) dx ## -- Could be the area under the graph of y = f(x) between x = 0 and x = 1 (depending on what the function is)
##\frac{\int_{x_0}^{x_1} f(x) dx}{x_1-x_0} ## -- Average value of f on the interval [0, 1]
##\frac{\int_{x_0}^{x_1} f(x) dx}{2} ## -- No significant meaning
## f(x_1) - f(x_0)## -- Vertical distance between two points on the graph of f
## \frac{f(x_1) - f(x_0)}{x_1-x_0}## -- Slope of the secant line between the points ##(x_0, f(x_0))## and ##(x_1, f(x_1))##
## \frac{f(x_1) - f(x_0)}{2}## -- No significant meaning
## \frac{f(x_1) + f(x_0)}{2} ## -- Average (or mean) of two function values
Bruno Tolentino said:
appears with very often. But my doubt is the following:
My head is confused, are to much equations and concepts disconnected. I know that the inverse analog of derivative is the primitive, but what's the inverse analog of the arithmetic mean?
None that I'm aware of.
Bruno Tolentino said:
If the AM of two numbers is (a+b)/2, so the analog inverse is (a-b)/2?
There's no such concept, as far as I know.
Bruno Tolentino said:
And what's the inverse analog of (a+b+c)/3?
There is none.
Bruno Tolentino said:
What's the difference between the equations that I posted above!?
Again, none of the things you posted is an equation. An equation states that two expressions are equal (i.e., has = in it).
Bruno Tolentino said:
What's the inverse analogo of each equation that I wrote above?
The question is meaningless.
 

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