Bullet conservation of momentum problem

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Homework Help Overview

The problem involves a bullet fired into a ballistic pendulum, where the bullet's initial speed is to be determined based on the bullet's exit speed and the pendulum's rise height. The subject area includes conservation of momentum and energy principles.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply conservation of momentum and mechanical energy to find the initial speed of the bullet. Some participants question the calculations and suggest double-checking the numbers used in the momentum equations.

Discussion Status

Participants are engaged in reviewing the calculations presented, with some guidance offered regarding the importance of avoiding premature rounding in calculations. There is acknowledgment of potential errors in the original poster's approach, but no consensus on a definitive solution has been reached.

Contextual Notes

There are indications that the original poster may have rounded numbers too early in their calculations, which could affect the accuracy of their results. The problem context involves specific mass and height values that are critical to the calculations.

BrainMan
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Homework Statement


A 7-g bullet is fired into a 1.5-kg ballistic pendulum. The bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 12 cm. Find the initial speed of the bullet.

Homework Equations


conservation of momentum

The Attempt at a Solution


First I tried to find the initial momentum of the bullet as if it did't penetrate the block
so .007vi = (1.507)vf
because I have two unknowns I used the conservation of mechanical energy to solve for vf
1/2(1.507)(vf2) = (1.507)(9.8)(.12)
vf = 1.54 m/s
then plug that into find the initial velocity
vi = 435.29 m/s
initial momentum = 3.05

Then I tried to find the momentum of the bullet exiting the block and add it to the initial momentum to get the total initial momentum.
200(.007) = 1.4
1.4 + 3.05 = 4.45
and finally I divided that by the mass to get the initial velocity 635.75 m/s. The correct answer is 529 m/s.
 
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BrainMan said:
vi = 435.29 m/s

How did you get this number?
BrainMan said:
0.007vi = (1.507)vf
...
vf = 1.54 m/s

From this? (If yes, then double check your numbers.)
 
Other than that, looks good!

P.S.
You should not round your numbers until the very end. (Try to solve the problem with just algebra and then plug in the numbers at the end.) The reason is that your answer will be slightly off.

(In this problem and another you've recently posted, you rounded before the end which caused your answers to be off by about half a percent, which isn't much, but in some problems rounding before the end will cause you to be off by more than half a percent, and in other problems half a percent could be a meaningful error.)
 
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Nathanael said:
Other than that, looks good!

P.S.
You should not round your numbers until the very end. (Try to solve the problem with just algebra and then plug in the numbers at the end.) The reason is that your answer will be slightly off.

(In this problem and another you've recently posted, you rounded before the end which caused your answers to be off by about half a percent, which isn't much, but in some problems rounding before the end will cause you to be off by more than half a percent, and in other problems half a percent could be a meaningful error.)

OK I see what I did! Thanks!
 

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