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The density of steel is known to be 7.8 x 10

^{3}kg/m

^{3}, while that of water is 1000 kg/m

^{3}.

A) While the steel hull is fully submerged in the water, what is the volume of water displaced by the hull?

*I really have no idea how to work this problem out.*

Buoyancy = m* density * V displaced * G

m=pv

B) What is the tension in the crane's cable when the hull is fully submerged?

*I believe this one is related to A*

Density * Volume * G = F m=(density) Volume

1000* 18000/10 *10

f=1.8 x 10

^{7}

C) What is the tension in the crane's cable when the hull is out of the water?

Ft= mg

Ft = 18,000 * 10 (class standard)

**Ft= 180,000N**