A crane lifts the 18,000kg steel hull of a ship out of the water.(adsbygoogle = window.adsbygoogle || []).push({});

The density of steel is known to be 7.8 x 10^{3}kg/m^{3}, while that of water is 1000 kg/m^{3}.

A) While the steel hull is fully submerged in the water, what is the volume of water displaced by the hull?I really have no idea how to work this problem out.

Buoyancy = m* density * V displaced * G

m=pv

B) What is the tension in the crane's cable when the hull is fully submerged?

I believe this one is related to A

Density * Volume * G = F m=(density) Volume

1000* 18000/10 *10

f=1.8 x 10^{7}

C) What is the tension in the crane's cable when the hull is out of the water?

Ft= mg

Ft = 18,000 * 10 (class standard)

Ft= 180,000N

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# Buoyancy of ship, volume displaced, and tension of crane (in/out) of water

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