Tension in and out of water in constant velocity

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SUMMARY

The discussion focuses on calculating the tension in a crane's cable while lifting an 18,000-kg steel hull of a ship at constant velocity. When the hull is submerged in water, the tension is influenced by the buoyant force acting on it, which must be accounted for in the calculation. The tension when the hull is completely out of the water equals the weight of the hull, which is 18,000 kg multiplied by the acceleration due to gravity (9.81 m/s²), resulting in a tension of 176,580 N. The confusion arises from the need to consider water displacement when submerged, which affects the net force acting on the hull.

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A crane lifts the 18,000-kg steel hull of a ship out of the water at constant velocity.

(A) Determine the tension in the crane’s cable when the hull is submerged in the water.


(B) Find the tension when the hull is completely out of the water.

I would have thought that B would just be the weight, but apparently that was wrong. And how do you find the amount of water displaced when the hull is submerged? I was thinking maybe A is the weight minus the displacement?

Thanks in advance for any help!
 
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Your answer to B looks right to me. What's your reason for saying it's wrong?
I agree with your answer to A too.
 

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