Buoyant Force and Displacement Volume of a Boat in Lake Superior

Click For Summary

Homework Help Overview

The discussion revolves around a problem involving buoyant force and the volume of displaced water for a boat in Lake Superior, with a total mass of 15,450 kg. Participants are exploring the relationship between the weight of the boat and the buoyant force acting on it, as well as the volume of water displaced.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the calculation of buoyant force using the formula Fb=mg and question the conversion of units from kg*m/s^2 to Newtons. There is also a focus on the relationship between the weight of the boat and the volume of displaced water, with some questioning the density of water needed for calculations.

Discussion Status

Participants are actively engaging with the problem, clarifying concepts related to buoyant force and unit conversions. There is recognition of the need for additional information, such as the density of water, to accurately determine the volume of displaced water.

Contextual Notes

There is an emphasis on the correct interpretation of units and the relationship between mass and volume in the context of buoyancy. The discussion highlights the importance of understanding density in relation to the problem at hand.

disneygirl828
Messages
6
Reaction score
0

Homework Statement


A boat full of people lazily drifts along in Lake Superior. The boat has a mass, including people of 15,450kg.
A. What is the buoyant force?

B. What is the volume of the displaced liquid in cubic meters?




The Attempt at a Solution


A. Fb=mg
Fb=?
m=15,450kg
g= 10m/s
(15450kg)(10m/s)
=154500kg*m/s^2
B.
=154500m^3
 
Physics news on Phys.org
disneygirl828 said:

Homework Statement


A boat full of people lazily drifts along in Lake Superior. The boat has a mass, including people of 15,450kg.
A. What is the buoyant force?

B. What is the volume of the displaced liquid in cubic meters?




The Attempt at a Solution


A. Fb=mg
Fb=?
m=15,450kg
g= 10m/s
(15450kg)(10m/s)
=154500kg*m/s^2
B.
=154500m^3

While "154500kg*m/s^2" is technically correct, it is usual practice to convert the "kg*m/s^2" units to its well-known designation "N" for Newtons, the unit of force.

The displaced water should be equivalent in weight to the weight of the boat. Your value for the volume of displaced water is too large. What is the density of water in kg/m3?
 
gneill said:
While "154500kg*m/s^2" is technically correct, it is usual practice to convert the "kg*m/s^2" units to its well-known designation "N" for Newtons, the unit of force.

The displaced water should be equivalent in weight to the weight of the boat. Your value for the volume of displaced water is too large. What is the density of water in kg/m3?
so the volume of the displaced water would be 15450kg? How do you convert kg*m/s^2 to Newtons?
 
disneygirl828 said:
so the volume of the displaced water would be 15450kg? How do you convert kg*m/s^2 to Newtons?

The volume of the displaced water would be that volume of water which has a mass of 15450kg. To find that volume you will need to know the density of water (kg/m3).

The Newton is defined to be 1 kg*m/s2.
 
Thank you SO much :)
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K