Buoyany and change in volume underwater

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Homework Help Overview

The discussion revolves around buoyancy and the change in volume of a swimmer underwater as they inhale. The original poster presents a scenario involving the apparent weight of a swimmer with full and empty lungs, seeking to determine the change in body volume without needing the weight in air.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between weight, buoyant force, and volume displacement. The original poster questions how to solve for the change in volume without the weight in air, while others suggest focusing on setting up equations to find the change in volume directly.

Discussion Status

Some participants provide guidance on setting up equations to approach the problem, indicating that the original poster may not need certain information. There is an ongoing exploration of how to apply the principles of buoyancy to both the swimmer's scenario and a separate problem involving a floating block of wood and a dog.

Contextual Notes

The original poster's inquiry is constrained by the need to find a solution without the weight in air, and the second problem introduces additional variables related to the block's displacement in water.

sweetpete28
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By breathing in deeply, you can change volume of your body. Suppose a swimmer underwater weighs wf = 23.4 N with his lungs full, and we = 48.0 N with lungs empty. Find change in body volume when swimmer inhales.

I know the apparent weight = weight in air - buoyant force and buoyant force = weight of displaced fluid = desnity of liquid x g x volume but how do I solve for the change in volume without weight in air??
 
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Just set up the equations and solve for the change in volume. You won't need the weight in air. (Note that you are finding the change in volume, not the volume.)
 
Yup! Just got that one...here is last one I need to finish in 20 min...

A rectangular block of wood (M = 260 kg) floats on a calm fresh water lake with do = 12.6 cm below the water. When a dog steps on the block, the block is pushed downward so that now it floads with d = 15.9 cm beneath the water. Find the mass of the dog.

any suggestions?
 
Just set up your force equations. Assume that the block remains upright and has some cross-sectional area A. (You won't need a numerical value.)
 

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