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1. The second person to leave also takes a breath as deep as possible by exhaling as far as possible (leaving a volume of 1.190 L in their lungs), and then slowly inhaling to increase their lung volume by 4.080 L. His body temperature is also 36.04 °C. This person breathes out all the way to the surface in order to maintain a constant lung volume. How many moles of gas remain in the lungs?

**Relevant equations:**

PV = nRT

**The attempt at a solution:**

i found the total volume of the lungs to be

Vtotal = 1.190L + 4.080L = 5.270L = 0.005270m^3

and using PV = nRT i found the number of moles at full capacity lungs

(3.00 x 101300)(0.005270) = n(8.314)(36.04+273.15)

n = 0.6230 moles

then i found the number of moles when the person exhales using PV = nRT

(3.00 x 101300)(0.004080 - 0.001190) = n(8.314)(36.04+273.15)

n = 0.365

∴ the change in moles is n = 0.6230 - 0.341 = 0.281mols

**BUT the actual answer is 0.208 mols and i don't know what i'm doing wrong HELP!!**