Caclulating Acceleration /w Coefficent

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SUMMARY

The discussion focuses on calculating the acceleration of an 80 kg baseball player sliding into third base, given a coefficient of kinetic friction of 0.70 and an initial speed of 8.23 m/s. The net force acting on the player is determined using the formula Fn = Fg = mg, resulting in a normal force of 784 N. The frictional force is calculated as F"mu"k = Fn"mu", yielding a frictional force of 548.8 N. Consequently, the acceleration is computed using the formula a = fnet/m, resulting in an acceleration of 6.86 m/s².

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  • Understanding of Newton's Second Law of Motion
  • Knowledge of kinetic friction and its coefficient
  • Familiarity with basic physics formulas for force and acceleration
  • Ability to perform calculations involving mass and gravitational force
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  • Learn about the effects of friction on motion in physics
  • Explore advanced topics in dynamics, such as deceleration and drag forces
  • Practice solving problems involving different coefficients of friction
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of motion and friction in real-world scenarios.

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Homework Statement


An 80kg baseball players slides into third base. The coefficient of kinetic friction between the payer and the ground is 0.70. if his speed at the start of the slide is 8.23?

a) calculate acceleration

No really sure how 2 solve this question
 
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Nvm didnt thinking it threw properly found the answer
 
Basically Fn = Fg = mg
80kg(9.8m/s(squared)
=784

F"mu"k= Fn"mu" Then a = fnet/m = 548.8N/80Kg =6.86m/s(squared)
=784(0.7)
=548.8

hope this can help some1 else
 

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